Question:
A water sample is contaminated with compound X (molar mass \(=120g~mol^{-1}\)). Its molality is \(10^{-4}m\). What is its concentration in ppm?
A water sample is contaminated with compound X (molar mass \(=120g~mol^{-1}\)). Its molality is \(10^{-4}m\). What is its concentration in ppm?
Show Hint
For dilute aqueous solutions, use shortcut: \(ppm=m\times M\times1000\)
Updated On: Jun 15, 2026
- 120
- 1200
- 12
- \(12\times10^{3}\)
Show Solution
Verified By Collegedunia
The Correct Option is A
Solution and Explanation
Concept:
Parts per million (ppm) expresses concentration as milligrams of solute per kilogram of solution.
Relation connecting molality and ppm:
\[
ppm=m\times M\times10^3
\]
where
\[
m=\text{molality}
\]
\[
M=\text{molar mass}
\]
Step 1: Write given data carefully. Molality given: \[ m=10^{-4} \] Molar mass: \[ M=120g/mol \]
Step 2: Use ppm relation. Formula: \[ ppm=m\times M\times10^6/1000 \] or directly \[ ppm=m\times M\times10^3 \] Substitute values. \[ ppm=10^{-4}\times120\times10^3 \]
Step 3: Perform numerical simplification. \[ ppm=120\times10^{-1}\times10^1 \] \[ ppm=120 \] Hence final concentration becomes \[ \boxed{120\;ppm} \]
Step 1: Write given data carefully. Molality given: \[ m=10^{-4} \] Molar mass: \[ M=120g/mol \]
Step 2: Use ppm relation. Formula: \[ ppm=m\times M\times10^6/1000 \] or directly \[ ppm=m\times M\times10^3 \] Substitute values. \[ ppm=10^{-4}\times120\times10^3 \]
Step 3: Perform numerical simplification. \[ ppm=120\times10^{-1}\times10^1 \] \[ ppm=120 \] Hence final concentration becomes \[ \boxed{120\;ppm} \]
Was this answer helpful?
0
0
Top TS EAMCET Chemistry Questions
- A, B and C are three biomolecules. The results of the tests performed on them are given below :A, B and C are respectively :
Molisch's lest Barfoed Test Biuret Test A Positive Negative Negativde B Positive Positive Negative C Negative Negative Positive - 1 mole of $H_2$ and 2 moles of $I_2$ are taken initially in a 2 litre vessel. The number of moles of $H_2$ at equilibrium is 0.2. Then the number of moles of $I_2$ and HI at equilibrium is
- The pH of a buffer containing equal molarconcentration of a weak base and its chloride ( $K_b$ for weak base = $2 \times 10^{-5}$, log 2 = 0.3) is
- Atomic radius (pm) of Al, Si, N and F respectively is
- Consider the following electrode process of a cell, $ {Cl^{-1} -> \frac{1}{2} Cl_2 + e^{-}}$ $ {[MCl + e^{-} -> M + Cl^{-} ] }$ If EMF of this cell is $-1.140\, V$ and $E^0$ value of the cell is $-0.55\,V$ at $298\,K$, the value of the equilibrium constant of the sparingly soluble salt MCl is in the order of
View More Questions
Top TS EAMCET Molality and Molarity Questions
Top TS EAMCET Questions
- A bag contains $5$ red balls, $3$ black balls and $4$ white balls are drawn at random. The probability that they are not of same colour is
- If $cosec\, \theta - \cot \theta = 2017$, then quadrant in which $\theta $ lies is
- If $a$ is a unit vector, then $| a \times \hat{ i }|^{2}+| a \times \hat{ j }|^{2}+| a \times \hat{ k }|^{2}=$
- $A$ straight line makes an intercept on the $Y$-axis twice as long as that on $X$-axis and is at a unit distance from the origin. Then the line is represented by the equations
- Let $S$ and $S'$ be the foci of an ellipse and B be one end of its minor axis. If $SBS'$ is an isosceles right angled triangle then the eccentricity of the ellipse is
View More Questions