Question:

Choose the paramagnetic species: A. $O_{2}^{2-}$, B. $NO^{+}$, C. $O_{2}$, D. $CO^{+}$, E. NO.}

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Odd electrons = Instant Paramagnetism!
Updated On: May 15, 2026
  • A, B and C only
  • B, C and D only
  • C, D and E only
  • A, B and E only
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The Correct Option is C

Solution and Explanation


Step 1: Concept
Paramagnetic species possess at least one unpaired electron.

Step 2: Meaning
Use molecular orbital theory or electron counting. Species with an odd number of total electrons are always paramagnetic.

Step 3: Analysis
A. $O_{2}^{2-}$ (18e): Diamagnetic. B. $NO^{+}$ (14e): Diamagnetic. C. $O_{2}$ (16e): Paramagnetic (2 unpaired electrons in $\pi^{*}$). D. $CO^{+}$ (13e): Paramagnetic (odd electron). E. NO (15e): Paramagnetic (odd electron).

Step 4: Conclusion
Species C, D, and E are paramagnetic. Final Answer: (C)
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