Question:
An electromagnetic wave propagating through vacuum, described by \( E = E_0 \sin(kx - \omega t) \), \( B = B_0 \sin(kx - \omega t) \), then:
An electromagnetic wave propagating through vacuum, described by \( E = E_0 \sin(kx - \omega t) \), \( B = B_0 \sin(kx - \omega t) \), then:
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The electric and magnetic field amplitudes in an electromagnetic wave are related by the speed of light, \( c = E_0 / B_0 \).
Updated On: Mar 3, 2025
- \( E_0 k = B_0 \omega \)
- \( E_0 \omega = B_0 k \)
- \( E_0 B_0 = \omega k \)
- \( E_0 B_0 = \sqrt{\omega k} \)
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The Correct Option is B
Solution and Explanation
For an electromagnetic wave, the electric and magnetic field strengths \( E_0 \) and \( B_0 \) are related by the speed of light in vacuum \( c \):
\[
E_0 = c B_0.
\]
The wave number \( k \) and angular frequency \( \omega \) are related to the speed of light as:
\[
c = \frac{\omega}{k}.
\]
Combining the two equations, we get:
\[
E_0 \omega = B_0 k.
\]
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