Question:
Atomic numbers of four elements A, B, C and D are (Z-1), (Z+2), Z and (Z+1) respectively. If Z=9, the type of bonding between A and B is
Atomic numbers of four elements A, B, C and D are (Z-1), (Z+2), Z and (Z+1) respectively. If Z=9, the type of bonding between A and B is
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Metal + Non-metal = Ionic (Electrovalent); Non-metal + Non-metal = Covalent.
Updated On: Jul 4, 2026
- Dative bond
- Polar Covalent bond
- Electrovalent bond
- Non polar Covalent bond
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The Correct Option is C
Solution and Explanation
Step 1: Concept
Determine the nature of the elements based on their atomic numbers.
Step 2: Meaning
$Z=9$ is Fluorine (non-metal). $A = Z-1 = 8$ is Oxygen (non-metal). $B = Z+2 = 11$ is Sodium (metal).
Step 3: Analysis
Bonding between a metal (Sodium) and a non-metal (Oxygen) typically involves the transfer of electrons.
Step 4: Conclusion
This transfer of electrons results in an electrovalent (ionic) bond. Final Answer: (C)
Determine the nature of the elements based on their atomic numbers.
Step 2: Meaning
$Z=9$ is Fluorine (non-metal). $A = Z-1 = 8$ is Oxygen (non-metal). $B = Z+2 = 11$ is Sodium (metal).
Step 3: Analysis
Bonding between a metal (Sodium) and a non-metal (Oxygen) typically involves the transfer of electrons.
Step 4: Conclusion
This transfer of electrons results in an electrovalent (ionic) bond. Final Answer: (C)
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