Let the son's present age be \(x\), which makes the father's present age \(7x\). Five years from now their ages become \(x+5\) and \(7x+5\), and the ratio between them is given as 11:3: \(\dfrac{7x+5}{x+5} = \dfrac{11}{3}\).
Cross-multiplying gives \(21x+15=11x+55\), which simplifies to \(10x=40\), so \(x=4\).
That makes the son 4 and the father 28, so their present ages add up to 32 years, matching option 4.