Question:

At 25∘C, the solubility product of Mg(OH)2 is 1.0×10−11. At which pH, will Mg2+ ions start precipitating in the form of Mg(OH)2 from a solution of 0.001MMg2+ ions ?

Updated On: Apr 1, 2026
  • 10

  • 15

  • 1

  • 20

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The Correct Option is A

Solution and Explanation

Explanation:
We know,Mg2++2OH−⇌Mg(OH)2Ksp=[Mg2+][OH−]2 (Equation for equilibrium)[OH−]=Ksp[Mg2+]=10−4∴pOH=4 and pH=10Hence, the correct answer is '10'.
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