Assuming ideal op-amps, the circuit represents:

A buffer amplifier, also known as a voltage follower, is a circuit configuration in which the input signal is directly coupled to the non-inverting terminal of the op-amp, and the output is connected to the inverting terminal. This results in the output voltage being equal to the input voltage, meaning the op-amp provides a high input impedance and a low output impedance without any amplification.
- In the case of a buffer, there is no difference in voltage between the input and output, making the circuit behave as a buffer or voltage follower.
Thus, the correct answer is Buffer (Option B).
The state space representation of a first-order system is \[ \dot{X} = -X + U, Y = X \] where \(X\) is the state variable, \(u\) is the control input and \(y\) is the controlled output. Let \(u = -KX\) be the control law. To place a closed-loop pole at \(-2\), the value of \(K\) is \(\underline{\hspace{1cm}}\).
Given an open-loop transfer function \(GH = \frac{100}{s}(s+100)\) for a unity feedback system with a unit step input \(r(t)=u(t)\), determine the rise time \(t_r\).
Consider a linear time-invariant system represented by the state-space equation: \[ \dot{x} = \begin{bmatrix} a & b -a & 0 \end{bmatrix} x + \begin{bmatrix} 1 0 \end{bmatrix} u \] The closed-loop poles of the system are located at \(-2 \pm j3\). The value of the parameter \(b\) is: