Question:

Assume a cell with the following reaction

\(\mathrm{Cu_{(s)} + 2Ag^{+}(1\times 10^{-3}\,M) \rightarrow Cu^{2+}(0.250\,M) + 2Ag_{(s)}}\)

\(E^{\Theta}_{cell} = 2.97\) V

\(E_{cell}\) for the above reaction is ______________ V. (Nearest integer)

[Given : log 2.5 = 0.3979, T = 298 K]

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Apply the Nernst equation with n = 2 and \(Q = [\mathrm{Cu^{2+}}]/[\mathrm{Ag^{+}}]^2\), using 0.0591 V at 298 K.
Updated On: Nov 4, 2026
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Correct Answer: 3

Solution and Explanation

n = 2 electrons. \(Q = \dfrac{[\mathrm{Cu^{2+}}]}{[\mathrm{Ag^{+}}]^2} = \dfrac{0.250}{(10^{-3})^2} = 2.5\times 10^{5}\)
Nernst equation at 298 K: \(E = E^{\Theta} - \dfrac{0.0591}{n}\log Q\)
\(\log Q = \log 2.5 + 5 = 5.3979\)
\(E = 2.97 - \dfrac{0.0591}{2}\times 5.3979 = 2.97 - 0.02955\times 5.3979 = 2.97 - 0.1595 = 2.81\) V
Nearest integer = 3
Answer: 3
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