As per the given figure, if $\frac{ dI }{ dt }=-1 A /$ s then the value of $V _{ AB }$ at this instant will be ______$V$

The correct answer is 30.
The differential equation for the circuit is given by:
\[ \frac{dI}{dt} = -1 \ \text{A/sec} \]
The equation for the potential difference across the circuit is:
\[ V_A - IR - L \frac{dI}{dt} - 12 = V_B \]
Substitute \(I = 2 \ \text{A}\), \(R = 12 \ \Omega\), \(L = 6 \ \text{H}\), and \(\frac{dI}{dt} = -1\):
\[ V_A - 2 \times 12 - 6(-1) - 12 = V_B \]
Simplify the equation:
\[ V_A - V_B = 36 - 6 = 30 \ \text{volts} \]
\(V_A - V_B = 30 \ \text{volts}\)
A conducting bar moves on two conducting rails as shown in the figure. A constant magnetic field \( B \) exists into the page. The bar starts to move from the vertex at time \( t = 0 \) with a constant velocity. If the induced EMF is \( E \propto t^n \), then the value of \( n \) is _____. 
MX is a sparingly soluble salt that follows the given solubility equilibrium at 298 K.
MX(s) $\rightleftharpoons M^{+(aq) }+ X^{-}(aq)$; $K_{sp} = 10^{-10}$
If the standard reduction potential for $M^{+}(aq) + e^{-} \rightarrow M(s)$ is $(E^{\circ}_{M^{+}/M}) = 0.79$ V, then the value of the standard reduction potential for the metal/metal insoluble salt electrode $E^{\circ}_{X^{-}/MX(s)/M}$ is ____________ mV. (nearest integer)
[Given : $\frac{2.303 RT}{F} = 0.059$ V]
An infinitely long straight wire carrying current $I$ is bent in a planar shape as shown in the diagram. The radius of the circular part is $r$. The magnetic field at the centre $O$ of the circular loop is :

The magnetic field is a field created by moving electric charges. It is a force field that exerts a force on materials such as iron when they are placed in its vicinity. Magnetic fields do not require a medium to propagate; they can even propagate in a vacuum. Magnetic field also referred to as a vector field, describes the magnetic influence on moving electric charges, magnetic materials, and electric currents.