Question:

Area of the circle in which a chord of length \(\sqrt{2}\) makes an angle \(\pi/2\) at the centre is

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Chord length depends on half the central angle.
Updated On: Mar 23, 2026
  • \(\pi/2\) sq units
  • \(2\pi\) sq units
  • \(\pi\) sq units
  • \(\pi/4\) sq units
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The Correct Option is C

Solution and Explanation


Step 1:
Chord length: \[ l=2R\sin\frac{\theta}{2} \]
Step 2:
Given \(\theta=\pi/2\), \[ \sqrt2=2R\sin\frac{\pi}{4}=2R\cdot\frac1{\sqrt2} \Rightarrow R=1 \]
Step 3:
\[ \text{Area}=\pi R^2=\pi \]
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