Question:
Area between $y^2=x$ and $y=|x|$ is:
Area between $y^2=x$ and $y=|x|$ is:
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Always check intersection points before setting area limits.
Updated On: Jun 10, 2026
- $\frac{1}{6}$
- $\frac{1}{3}$
- $\frac{1}{2}$
- $\frac{2}{3}$
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The Correct Option is A
Solution and Explanation
Intersection:
\[
\sqrt{x}=x \Rightarrow x=0,1
\]
Area:
\[
A=\int_0^1 (\sqrt{x}-x)dx
\]
\[
= \left[\frac{2}{3}x^{3/2}-\frac{x^2}{2}\right]_0^1
= \frac{2}{3}-\frac{1}{2}
= \frac{1}{6}
\]
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