Step 1: Understanding the Concept:
Calendar problems rely on counting the number of odd days.
An ordinary year contains 365 days, while a leap year contains 366 days.
Any day of the week repeats itself after every 7 days.
Key Formula or Approach:
The number of odd days in a time interval is calculated as:
\[ \text{Odd Days} = \text{Total Days} \pmod 7 \]
- An ordinary year has $365 \text{ days} = 52 \text{ weeks} + 1 \text{ day}$ (1 odd day).
- A leap year has $366 \text{ days} = 52 \text{ weeks} + 2 \text{ days}$ (2 odd days).
Step 2: Detailed Explanation:
The period in question is from April 16, 2021, to April 16, 2022.
Let us determine if this period contains the leap day (February 29):
- The year 2021 is a non-leap year.
- The year 2022 is a non-leap year.
- Hence, February 2022 has only 28 days.
Since the interval does not span across a February 29th leap day, the total number of days in this exact one-year period is 365 days.
Calculate the number of odd days:
\[ 365 \pmod 7 = 1 \text{ odd day} \]
Because we are moving backward in time (from April 16, 2022 to April 16, 2021), we subtract the odd day:
\[ \text{Day on April 16, 2021} = \text{Day on April 16, 2022} - 1 \text{ odd day} \]
Given that April 16, 2022, is a Saturday:
\[ \text{Day on April 16, 2021} = \text{Saturday} - 1 = \text{Friday} \]
Step 3: Final Answer:
The day of the week on April 16, 2021, was Friday.