Question

Find the average of number bags transported by trucks 2 and 6.

• A. 4800
• B. 3000
• C. 2400
• D. 3200
• A. 3240
• B. 4580
• C. 3860
• D. 4440
• A. 13:12
• B. 15:16
• C. 10:9
• D. 12:7
• A. 6.5%
• B. 15%
• C. 12.5%
• D. 7.5%
• A. 200
• B. 160
• C. 320
• D. 180

Answer 1

The Correct Option is B

Since, 1200 articles are not transported by truck 1 therefore, they must have been transported by truck 3
Also, a fixed number of articles have to be transported always.
Total articles transported by truck 3 = (\(\frac{4500}{0.75}\)) = 6000
Therefore, fixed number of articles transported by each truck = 6000 –1200 = 4800
Therefore,
Number of articles not transported by truck 2 = 0.2 × 4800 = 960 Similarly,

Truck	Total number of articles have to be transported	Number of articles transported	Number of articles not transported
1	4800	4800 – 1200 =3600	1200
2	4800	4800 – 960 =3840	960
3	4800 + 1200 = 6000	4500	6000 – 4500 =1500
4	4800 + 960 = 5760	5760 – 2880 =2880	2880
5	4800 + 1500 = 6300	0.6 × 6300 =3780	6300 – 3780 =2520
6	4800 + 2880 = 7680	5760	7680 – 5760 =1920

Now, Sum of number of articles transported by each of the given trucks =3600 + 3840 + 4500 + 2880 + 3780 + 5760 = 24360
Sum of number of balls transported by given 6 trucks = 24360 – 12360 =12000
Therefore,

Truck	Total number of articles transported	Number of balls transported	Number of bags transported
1	3600	0.25 × 12000 =3000	3600 – 3000 =600
2	3840	0.1 × 12000 =1200	3840 – 1200 =2640
3	4500	0.05 × 12000 =600	4500 – 600 =3900
4	2880	0.15 × 12000 =1800	2880 – 1800 =1080
5	3780	0.25 × 12000 =3000	3780 – 3000 =780
6	5760	0.2 × 12000 =2400	5760 – 2400 =3360

Required average =\(\frac{ (3360 + 2640)}{2}\)=3000
So, the correct option is (B) : 3000.

Answer 2

Since, 1200 articles are not transported by truck 1 therefore, they must have been transported by truck 3
Also, a fixed number of articles have to be transported always.
Total articles transported by truck 3 = (\(\frac{4500}{0.75}\)) = 6000
Therefore, fixed number of articles transported by each truck = 6000 –1200 = 4800
Therefore,
Number of articles not transported by truck 2 = 0.2 × 4800 = 960 Similarly,

Truck	Total number of articles have to be transported	Number of articles transported	Number of articles not transported
1	4800	4800 – 1200 =3600	1200
2	4800	4800 – 960 =3840	960
3	4800 + 1200 = 6000	4500	6000 – 4500 =1500
4	4800 + 960 = 5760	5760 – 2880 =2880	2880
5	4800 + 1500 = 6300	0.6 × 6300 =3780	6300 – 3780 =2520
6	4800 + 2880 = 7680	5760	7680 – 5760 =1920

Now, Sum of number of articles transported by each of the given trucks =3600 + 3840 + 4500 + 2880 + 3780 + 5760 = 24360
Sum of number of balls transported by given 6 trucks = 24360 – 12360 =12000
Therefore,

Truck	Total number of articles transported	Number of balls transported	Number of bags transported
1	3600	0.25 × 12000 =3000	3600 – 3000 =600
2	3840	0.1 × 12000 =1200	3840 – 1200 =2640
3	4500	0.05 × 12000 =600	4500 – 600 =3900
4	2880	0.15 × 12000 =1800	2880 – 1800 =1080
5	3780	0.25 × 12000 =3000	3780 – 3000 =780
6	5760	0.2 × 12000 =2400	5760 – 2400 =3360

Required number of students = 2520 + 1920 = 4440
So, the correct option is (D) : 4440.

Answer 3

Since, 1200 articles are not transported by truck 1 therefore, they must have been transported by truck 3
Also, a fixed number of articles have to be transported always.
Total articles transported by truck 3 = (\(\frac{4500}{0.75}\)) = 6000
Therefore, fixed number of articles transported by each truck = 6000 –1200 = 4800
Therefore,
Number of articles not transported by truck 2 = 0.2 × 4800 = 960 Similarly,

Truck	Total number of articles have to be transported	Number of articles transported	Number of articles not transported
1	4800	4800 – 1200 =3600	1200
2	4800	4800 – 960 =3840	960
3	4800 + 1200 = 6000	4500	6000 – 4500 =1500
4	4800 + 960 = 5760	5760 – 2880 =2880	2880
5	4800 + 1500 = 6300	0.6 × 6300 =3780	6300 – 3780 =2520
6	4800 + 2880 = 7680	5760	7680 – 5760 =1920

Now, Sum of number of articles transported by each of the given trucks =3600 + 3840 + 4500 + 2880 + 3780 + 5760 = 24360
Sum of number of balls transported by given 6 trucks = 24360 – 12360 =12000
Therefore,

Truck	Total number of articles transported	Number of balls transported	Number of bags transported
1	3600	0.25 × 12000 =3000	3600 – 3000 =600
2	3840	0.1 × 12000 =1200	3840 – 1200 =2640
3	4500	0.05 × 12000 =600	4500 – 600 =3900
4	2880	0.15 × 12000 =1800	2880 – 1800 =1080
5	3780	0.25 × 12000 =3000	3780 – 3000 =780
6	5760	0.2 × 12000 =2400	5760 – 2400 =3360

Required ratio = 3900:3600 = 13:12
So, the correct option is (A) : 13:12.

Answer 4

Since, 1200 articles are not transported by truck 1 therefore, they must have been transported by truck 3
Also, a fixed number of articles have to be transported always.
Total articles transported by truck 3 = (\(\frac{4500}{0.75}\)) = 6000
Therefore, fixed number of articles transported by each truck = 6000 –1200 = 4800
Therefore,
Number of articles not transported by truck 2 = 0.2 × 4800 = 960 Similarly,

Truck	Total number of articles have to be transported	Number of articles transported	Number of articles not transported
1	4800	4800 – 1200 =3600	1200
2	4800	4800 – 960 =3840	960
3	4800 + 1200 = 6000	4500	6000 – 4500 =1500
4	4800 + 960 = 5760	5760 – 2880 =2880	2880
5	4800 + 1500 = 6300	0.6 × 6300 =3780	6300 – 3780 =2520
6	4800 + 2880 = 7680	5760	7680 – 5760 =1920

Now, Sum of number of articles transported by each of the given trucks =3600 + 3840 + 4500 + 2880 + 3780 + 5760 = 24360
Sum of number of balls transported by given 6 trucks = 24360 – 12360 =12000
Therefore,

Truck	Total number of articles transported	Number of balls transported	Number of bags transported
1	3600	0.25 × 12000 =3000	3600 – 3000 =600
2	3840	0.1 × 12000 =1200	3840 – 1200 =2640
3	4500	0.05 × 12000 =600	4500 – 600 =3900
4	2880	0.15 × 12000 =1800	2880 – 1800 =1080
5	3780	0.25 × 12000 =3000	3780 – 3000 =780
6	5760	0.2 × 12000 =2400	5760 – 2400 =3360

Required percentage = {\(\frac{(1080 – 960)}{960}\)} × 100 = 12.5%
So, the correct option is (C) : 12.5%.

Answer 5

Since, 1200 articles are not transported by truck 1 therefore, they must have been transported by truck 3
Also, a fixed number of articles have to be transported always.
Total articles transported by truck 3 = (\(\frac{4500}{0.75}\)) = 6000
Therefore, fixed number of articles transported by each truck = 6000 –1200 = 4800
Therefore,
Number of articles not transported by truck 2 = 0.2 × 4800 = 960 Similarly,

Truck	Total number of articles have to be transported	Number of articles transported	Number of articles not transported
1	4800	4800 – 1200 =3600	1200
2	4800	4800 – 960 =3840	960
3	4800 + 1200 = 6000	4500	6000 – 4500 =1500
4	4800 + 960 = 5760	5760 – 2880 =2880	2880
5	4800 + 1500 = 6300	0.6 × 6300 =3780	6300 – 3780 =2520
6	4800 + 2880 = 7680	5760	7680 – 5760 =1920

Now, Sum of number of articles transported by each of the given trucks =3600 + 3840 + 4500 + 2880 + 3780 + 5760 = 24360
Sum of number of balls transported by given 6 trucks = 24360 – 12360 =12000
Therefore,

Truck	Total number of articles transported	Number of balls transported	Number of bags transported
1	3600	0.25 × 12000 =3000	3600 – 3000 =600
2	3840	0.1 × 12000 =1200	3840 – 1200 =2640
3	4500	0.05 × 12000 =600	4500 – 600 =3900
4	2880	0.15 × 12000 =1800	2880 – 1800 =1080
5	3780	0.25 × 12000 =3000	3780 – 3000 =780
6	5760	0.2 × 12000 =2400	5760 – 2400 =3360

Required difference = 780 – 600 = 180
So, the correct option is (D) : 180.