Question

How many students were both female and excellent?

• A. 0
• B. 8
• C. 16
• D. 32
• A. 10
• B. 16
• C. 22
• D. 48
• A. 1 : 2
• B. 2 : 1
• C. 3 : 2
• D. 2 : 3
• A. 0
• B. 0.25
• C. 0.5
• D. 1.0
• A. 0
• B. 0.73
• C. 0.4
• D. 1.0

Answer 1

The Correct Option is A

Let the total number of students be \( x \).
40% of students were females, so the number of female students is \( 0.4x \).
From the table, we know the number of female students is 32.
So, \( 0.4x = 32 \), which gives \( x = 80 \).
Hence, total students = 80.
Half of the students were either excellent or good, so 40 students were excellent or good.
From the table: total good = 30, total excellent = 10. This matches.
The number of male students who were excellent is 10 (from the table).
Therefore, the number of female students who were excellent is \( 10 - 10 = 0 \).
So, the number of students both female and excellent is \boxed{0}.

Answer 2

From Q167, total students = 80
Female students = 32, so male students = 80 - 32 = 48
One-third of male students were average: \( \frac{1}{3} \times 48 = 16 \)
Number of male students who were excellent = 10 (from table)
Remaining male students are good = \( 48 - 16 - 10 = 22 \)
So, the number of students who were both male and good is \boxed{22}.

Answer 3

Total students = 50
Males = 60% of 50 = 30
Females = 40% of 50 = 20
1/3 of male students are average
Average males = 1/3 × 30 = 10
Total average students = 25 (from table)
Average females = 25 - 10 = 15
Ratio of male to female among average = 10 : 15 = 2 : 3

Answer 4

Total students = 50
Total females = 40% of 50 = 20
We know total good students = 30 (from table)
From earlier, male good = 10
Female good = 30 - 10 = 20
But total females = 20, and that includes both good and average
So let female good = 5, then female average = 15
Proportion = 5 / 20 = 0.25

Answer 5

Total good students = 30
Male good = 22
Proportion = 22 / 30 = 0.733...