Question:

Answer question given below by reading the following information:
Elle is three times older than Yogesh; Zaheer is half the age of Wahida. Yogesh is older than Zaheer.
Which of the following can be inferred?

Show Hint

To solve inequality puzzles quickly, assign simple arbitrary numbers that satisfy the conditions:
Let $Z = 10 \implies W = 20$.
Since $Y > Z$, let $Y = 11 \implies E = 3 \times 11 = 33$.
Comparing the values: $E (33) > W (20)$, which confirms that Elle is older than Wahida.
  • Yogesh is older than Wahida.
  • Elle is older than Wahida.
  • Elle may be younger than Wahida.
  • Zaheer is older than Elle.
Show Solution
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The Correct Option is B

Solution and Explanation

Step 1: Understanding the Concept:
This problem requires setting up mathematical inequalities based on the relative age relationships of the four individuals.
Detailed Explanation:
Let the ages of Elle, Yogesh, Zaheer, and Wahida be represented by $E$, $Y$, $Z$, and $W$ respectively.
From the given statements, we can write the following relations:
1. $E = 3Y \implies Y = \frac{E}{3}$
2. $Z = \frac{W}{2} \implies W = 2Z$
3. $Y > Z$
Let us substitute $Y$ and $Z$ into the third inequality: \[ \frac{E}{3} > \frac{W}{2} \] Cross-multiplying (since ages are positive quantities, the direction of the inequality remains unchanged): \[ 2E > 3W \] Divide both sides by 2: \[ E > 1.5W \] Since $W$ must be a positive number (representing a person's age), $1.5W$ is strictly greater than $W$: \[ E > 1.5W > W \implies E > W \] Therefore, Elle is strictly older than Wahida.

Step 2: Final Answer:

The valid inference is "Elle is older than Wahida", which corresponds to Option (B).
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