Each triangular piece is isosceles with sides 30 cm, 60 cm, 60 cm. Instead of Heron's formula, drop a perpendicular from the apex to the 30 cm base, splitting it into two equal halves of 15 cm each.
By the Pythagorean theorem, the height is:
\[h=\sqrt{60^{2}-15^{2}}=\sqrt{3600-225}=\sqrt{3375}=15\sqrt{15}\text{ cm}\]
Area of one triangle:
\[\frac{1}{2}\times30\times15\sqrt{15}=225\sqrt{15}\text{ cm}^{2}\]
Total area for 10 triangles:
\[10\times225\sqrt{15}=2250\sqrt{15}\text{ cm}^{2}\]
Since the umbrella uses two colours in equal shares, cloth required per colour:
\[\frac{2250\sqrt{15}}{2}=1125\sqrt{15}\text{ cm}^{2}\]
The cloth required per colour is \(1125\sqrt{15}\text{ cm}^{2}\).
Hence, the correct answer is Option B: \(1125\sqrt{15}\).