Question:

An organic compound \(P\) of molecular formula \( \mathrm{C_6H_{12}O_3} \) gives positive iodoform test but negative Tollens’ test. When \(P\) is treated with dilute acid, it produces \(Q\). \(Q\) gives positive Tollens’ test and also iodoform test. Identify compound \(P\).

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Remember:
  • Iodoform test detects: \[ \mathrm{CH_3CO-} \] group.
  • Tollens’ reagent detects aldehydes.
  • Ketals/acetals hydrolyse back to carbonyl compounds in acidic medium.
Updated On: Jun 3, 2026
  • \( \mathrm{CH_3COCH(OCH_3)CH_2OCH_3} \)
  • \( \mathrm{CH_3COCH_2CH(OCH_3)_2} \)
  • \( \mathrm{HCOCH_2CH_2CH(OCH_3)_2} \)
  • \( \mathrm{CH_3COC(OCH_3)_2CH_3} \)
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The Correct Option is D

Solution and Explanation

Concept: Iodoform test is given by compounds containing: \[ \mathrm{CH_3CO-} \] group or compounds oxidisable to it. Tollens’ reagent gives positive test mainly with aldehydes. Acetals and ketals on hydrolysis with dilute acid regenerate carbonyl compounds.

Step 1:
Analysing properties of compound \(P\). Compound \(P\):
  • Gives positive iodoform test
  • Gives negative Tollens’ test
Therefore:
  • \(P\) must contain methyl ketone functionality or masked methyl ketone.
  • It should not contain free aldehyde group.


Step 2:
Analysing compound \(Q\). On hydrolysis with dilute acid: \[ P \rightarrow Q \] and \(Q\):
  • Gives positive Tollens’ test
  • Gives positive iodoform test
A compound giving both tests is: \[ \mathrm{CH_3CHO} \] that is ethanal. Ethanal:
  • Gives Tollens’ test because it is an aldehyde.
  • Gives iodoform test because it contains: \[ \mathrm{CH_3CHO} \]


Step 3:
Identifying the structure of \(P\). Option (4): \[ \mathrm{CH_3COC(OCH_3)_2CH_3} \] is a ketal derivative. On acidic hydrolysis: \[ \mathrm{CH_3COC(OCH_3)_2CH_3} \] regenerates: \[ \mathrm{CH_3CHO} \] which satisfies both:
  • Positive Tollens’ test
  • Positive iodoform test
Hence, option (4) is correct. \[ \boxed{(4)} \]
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