Question:

An organic compound [A], molecular formula \(\mathrm{C_{10}H_{20}O_2}\) was hydrolyzed with dilute sulphuric acid to give a carboxylic acid [B] and an alcohol [C]. Oxidation of [C] with \(\mathrm{CrO_3 - H_2SO_4}\) produced [B]. Which of the following strucutres are not possible for [A]?

Show Hint

[B] and [C] must have the same carbon skeleton and [C] must be a primary alcohol; also the ester must be \(\mathrm{C_{10}H_{20}O_2}\).
Updated On: Nov 5, 2026
  • \(\mathrm{(CH_3)_3-C-COOCH_2C(CH_3)_3}\)
  • \(\mathrm{CH_3CH_2CH_2COOCH_2CH_2CH_2CH_3}\)
Show Solution
collegedunia
Verified By Collegedunia

The Correct Option is B

Solution and Explanation

For oxidation of [C] to give [B], the acid and alcohol must have the same number of carbons and skeleton, and [C] must be a primary alcohol.
(1) pivalic acid + neopentyl alcohol (both 5 C, alcohol primary and oxidises to pivalic acid): possible.
(2) butanoic acid + butan-1-ol: formula is \(\mathrm{C_8H_{16}O_2}\), not \(\mathrm{C_{10}H_{20}O_2}\) (4 C + 4 C): not possible.
(3) 2-methylbutanoic acid + 2-methylbutan-1-ol: 5 C + 5 C, \(\mathrm{C_{10}H_{20}O_2}\), alcohol primary and oxidises to 2-methylbutanoic acid: possible.
(4) 3-methylpentanoic acid (6 C) + butan-2-ol (4 C, a secondary alcohol that gives a ketone, not the acid): not possible.
Not possible: options (2) and (4).
Answer: (2) and (4)
Was this answer helpful?
0
0