h=ut+\(\frac{1}{2}gt^2\)
t=\(\frac{√2h}{g}\)=2 sec
x=Vt=5 m
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,

What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)
The distance between any two points is the length or distance of the line segment joining the points. There is only one line that is passing through two points. So, the distance between two points can be obtained by detecting the length of this line segment joining these two points. The distance between two points using the given coordinates can be obtained by applying the distance formula.
