Question

An LVDT produces an output of \(5\,\mathrm{mV/mm}\) sensitivity. For an excitation of \(10\,\mathrm{V}\) and displacement of \(2\,\mathrm{mm}\), the output voltage is

• A. \(50\,\mathrm{mV}\)
• B. \(100\,\mathrm{mV}\)
• C. \(200\,\mathrm{mV}\)
• D. \(1\,\mathrm{V}\)

Hint:

For an LVDT, \[ \boxed{ V_o=(\text{Sensitivity})\times(\text{Excitation})\times(\text{Displacement}) } \] where sensitivity is expressed in \(\mathrm{mV/(V\cdot mm)}\).

Answer 1

The Correct Option is B

Step 1: Calculate the output using the given sensitivity. The output voltage is \[ V_o = (\text{Sensitivity})\times(\text{Excitation Voltage})\times(\text{Displacement}). \] Given, \[ \text{Sensitivity}=5\ \frac{\text{mV}}{\text{V}\cdot\text{mm}}, \] \[ \text{Excitation}=10\ \text{V}, \] \[ \text{Displacement}=2\ \text{mm}. \]

Step 2: Substitute the values. \[ V_o = 5\times10\times2 = 100\ \text{mV}. \] Hence, \[ \boxed{100\ \text{mV}} \] Therefore, \[ \boxed{(B)} \] is the correct answer.