Question:
An equation of a plane parallel to the plane \( x - 2y + 2z - 5 = 0 \) and which is at one unit distance from the origin is:
An equation of a plane parallel to the plane \( x - 2y + 2z - 5 = 0 \) and which is at one unit distance from the origin is:
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To find a parallel plane at a certain distance from the origin, use the formula for the distance from the point to the plane and adjust the constant accordingly.
Updated On: Mar 18, 2026
- \( x - 2y + 2z - 1 = 0 \)
- \( x - 2y + 2z + 5 = 0 \)
- \( x - 2y + 2z - 3 = 0 \)
- \( x - 2y + 2z + 1 = 0 \)
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The Correct Option is C
Solution and Explanation
The equation of the plane at a distance of 1 unit from the origin parallel to the given plane is found by using the formula for the distance from the origin to the plane. The correct equation is \( x - 2y + 2z - 3 = 0 \).
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