Question:

An engine delivers \(1000\text{ watt}\) of power with \(80\%\) efficiency. The input power is

Show Hint

Efficiency \(=\frac{\text{Output power}}{\text{Input power}}\). Always convert percentage efficiency into decimal before calculation.
  • \(800\text{ W}\)
  • \(1000\text{ W}\)
  • \(1250\text{ W}\)
  • \(1500\text{ W}\)
Show Solution
collegedunia
Verified By Collegedunia

The Correct Option is C

Solution and Explanation

We are given output power: \[ P_{\text{out}}=1000\text{ W}. \] Efficiency is: \[ \eta=80\%. \] Convert percentage into decimal: \[ \eta=\frac{80}{100}=0.8. \] Efficiency is defined as: \[ \eta=\frac{P_{\text{out}}}{P_{\text{in}}}. \] We need to find input power: \[ P_{\text{in}}. \] Rearrange the formula: \[ P_{\text{in}}=\frac{P_{\text{out}}}{\eta}. \] Substitute the values: \[ P_{\text{in}}=\frac{1000}{0.8}. \] \[ P_{\text{in}}=1250\text{ W}. \] Therefore, the input power is: \[ 1250\text{ W}. \]
Was this answer helpful?
0
0