An element X has a body centred cubic (bcc) structure with a cell edge of 200 pm. The density of the element is 5 g cm\( - \)3. The number of atoms present in 300 g of the element X is _______________.
Given : Avogadro constant, NA = 6.0 \( \times \) 1023 mol\( - \)1.
An element X has a body centred cubic (bcc) structure with a cell edge of 200 pm. The density of the element is 5 g cm\( - \)3. The number of atoms present in 300 g of the element X is _______________.
Given : Avogadro constant, NA = 6.0 \( \times \) 1023 mol\( - \)1.
Show Hint
- 5 NA
- 6 NA
- 15 NA
- 25 NA
The Correct Option is D
Solution and Explanation
Step 2: Mass of one unit cell \(= \rho a^3 = 5\times8\times10^{-24} = 4\times10^{-23}\) g. A bcc cell has Z = 2 atoms.
Step 3: Mass per atom \(= 2\times10^{-23}\) g.
Step 4: Atoms in 300 g \(= \dfrac{300}{2\times10^{-23}} = 1.5\times10^{25} = 25\times(6.0\times10^{23}) = 25\,N_A\).
Answer: (D) 25 NA
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