The ionic character of a compound depends on the difference in ionisation enthalpy and electron gain enthalpy. The larger the difference, the greater the ionic character. A compound with a more negative electron gain enthalpy will result in a stronger ionic bond. Given that the electron gain enthalpy values for elements A, B, C, and D are as follows:
- \( {A} \) has \( -328 \, {kJ/mol} \)
- \( {B} \) has \( -349 \, {kJ/mol} \)
- \( {C} \) has \( -325 \, {kJ/mol} \)
- \( {D} \) has \( -295 \, {kJ/mol} \)
The order of ionic character is given by the electron gain enthalpy, where \( {D} \) has the highest ionic character and \( {A} \) has the least. Thus, the correct order is (3): \( {ED}>{EC}>{EB}>{EA} \).
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)