Magnetic Force on a Moving Charge:
When a charged particle, such as an electron, moves in a magnetic field, it experiences a force given by:
\[ \vec{F} = q (\vec{v} \times \vec{B}) \]
where \(\vec{v}\) is the velocity of the particle and \(\vec{B}\) is the magnetic field.
The direction of the force is perpendicular to both \(\vec{v}\) and \(\vec{B}\).
Magnetic Field Inside a Solenoid:
Inside a long solenoid carrying current, the magnetic field \(\vec{B}\) is uniform and directed along the axis of the solenoid.
Since the electron is moving along the axis, its velocity \(\vec{v}\) is also parallel to \(\vec{B}\).
No Magnetic Force Due to Parallel \(\vec{v}\) and \(\vec{B}\):
Since \(\vec{v} \parallel \vec{B}\), the cross product \(\vec{v} \times \vec{B} = 0\).
Therefore, the magnetic force \(\vec{F} = 0\), and the electron will not experience any force due to the magnetic field.
Conclusion:
The electron will continue to move with uniform velocity along the axis of the solenoid, as there is no force acting on it to change its state of motion.
Match the LIST-I with LIST-II:
| List-I | List-II | ||
| A. | Radio-wave | I. | is produced by Magnetron valve |
| B. | Micro-wave | II. | due to change in the vibrational modes of atoms |
| C. | Infrared-wave | III. | due to inner shell electrons moving from higher energy level to lower energy level |
| D. | X-ray | IV. | due to rapid acceleration of electrons |
Choose the correct answer from the options given below:

In the following \(p\text{–}V\) diagram, the equation of state along the curved path is given by \[ (V-2)^2 = 4ap, \] where \(a\) is a constant. The total work done in the closed path is: 