Question:
An electric dipole with dipole moment $2 \times 10^{-10}\, C \cdot m$ is aligned at an angle $30^\circ$ with the direction of a uniform electric field of $10^4\, N/C$. The magnitude of the torque acting on the dipole is
An electric dipole with dipole moment $2 \times 10^{-10}\, C \cdot m$ is aligned at an angle $30^\circ$ with the direction of a uniform electric field of $10^4\, N/C$. The magnitude of the torque acting on the dipole is
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Torque depends on dipole moment, electric field, and the sine of the angle between them.
Updated On: Mar 16, 2026
- \(10^{-6}\, N \cdot m\)
- \(10^{-5}\, N \cdot m\)
- \(10^{-4}\, N \cdot m\)
- \(10^{-3}\, N \cdot m\)
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The Correct Option is A
Solution and Explanation
Torque \(\tau\) on an electric dipole is: \[ \tau = p E \sin \theta \] Given: \[ p = 2 \times 10^{-10}\, C \cdot m, \quad E = 10^4\, N/C, \quad \theta = 30^\circ \] Calculate: \[ \tau = 2 \times 10^{-10} \times 10^4 \times \sin 30^\circ = 2 \times 10^{-6} \times \frac{1}{2} = 10^{-6}\, N \cdot m \]
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