An alkane on complete combustion required 8 moles of O2. Find out the number of carbon and hydrogen in the alkane.
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Correct Answer: 10
Solution and Explanation
The general combustion reaction for an alkane is:
\[C_nH_{2n+2} + O_2 \rightarrow CO_2 + H_2O\]
For complete combustion, the number of moles of oxygen required is given by:
\[\text{Oxygen required} = \left( n + \frac{2n+2}{2} \right) = \frac{3n+2}{2}\]
Given that 8 moles of oxygen are required for complete combustion, we set up the equation:
\[\frac{3n+2}{2} = 8\]
Multiplying both sides by 2:
\[3n + 2 = 16\]
Solving for \(n\):
\[3n = 14\]
\[n = \frac{14}{3} \approx 4.67\]
Since the number of carbon atoms must be an integer, the alkane is approximately C4H10. Thus, the alkane has 4 carbon atoms and 10 hydrogen atoms.
\[\boxed{C_4H_{10}}\]
Hence, the correct number of carbon and hydrogen atoms is C4H10.
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