Question

An aircraft executes a horizontal loop of radius 1.00 km with a steady speed of $900~km/h$. Its centripetal acceleration is ________.

• A. $0.4~m/s^{2}$
• B. $250~m/s^{2}$
• C. $62.5~m/s^{2}$
• D. $6.38~m/s^{2}$

Hint:

Always convert speed to m/s and radius to meters before calculating acceleration.

Answer 1

The Correct Option is C

Step 1: Concept
Centripetal acceleration ($a_c$) = $v^2 / r$.
Step 2: Analysis
Radius ($r$) = 1.00 km = 1000 m. Speed ($v$) = 900 km/h. To convert to m/s: $900 \times (5/18) = 250$ m/s.
Step 3: Calculation
$a_c = (250)^2 / 1000 = 62500 / 1000 = 62.5$ m/$s^2$.
Step 4: Conclusion
Hence, the centripetal acceleration is 62.5 m/$s^2$.
Final Answer:(C)