Question:

An AC source of \(220\,V\) and \(50\,Hz\) is connected to an RLC circuit having resistance \(10\,\Omega\). The power factor is \(0.5\). Find the average power consumed.

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Average power in AC circuits is \[ P=VI\cos\phi. \] Only the active component of current contributes to power consumption.
  • \(605\,W\)
  • \(2420\,W\)
  • \(1210\,W\)
  • \(2200\,W\)
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The Correct Option is B

Solution and Explanation

Concept: The average power consumed in an AC circuit is \[ P=VI\cos\phi \] where \(\cos\phi\) is the power factor. Current is obtained using \[ I=\frac{V}{R}. \]

Step 1:
Calculate current. Given, \[ V=220\,V \] \[ R=10\,\Omega \] Hence, \[ I=\frac{220}{10} \] \[ I=22\,A \]

Step 2:
Calculate average power. Power factor, \[ \cos\phi=0.5 \] Therefore, \[ P=VI\cos\phi \] \[ =(220)(22)(0.5) \] \[ =2420\,W \]

Step 3:
Compare with the options. The calculated value is \[ 2420\,W \] Thus the correct answer is \[ \boxed{(B)} \]
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