Question:
Among the gases \(a, b, c, d, e\) and \(f\), the gases that show only positive deviation from ideal behavior at all pressures in the graph are
Among the gases \(a, b, c, d, e\) and \(f\), the gases that show only positive deviation from ideal behavior at all pressures in the graph are
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For real gases, \(Z\gt 1\) indicates positive deviation due to dominant repulsive forces, while \(Z\lt 1\) indicates negative deviation due to dominant attractive forces.
Updated On: Jun 15, 2026
- \(b, c\) only
- \(b, c, a\) only
- \(d, e\) only
- \(d, e, f\) only
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The Correct Option is A
Solution and Explanation
Step 1: Understand the graph.
The graph shows variation of compressibility factor \(Z\) with pressure \(P\).
For an ideal gas,
\[ Z=1 \] at all pressures.
Step 2: Identify positive deviation.
A gas shows positive deviation from ideal behavior when
\[ Z\gt 1 \] This means the gas curve should remain above the line \(Z=1\) at all pressures.
Step 3: Observe the given curves.
From the graph, gases \(b\) and \(c\) remain above \(Z=1\) for all pressures.
Therefore, they show only positive deviation from ideal behavior.
Step 4: Eliminate other gases.
Gas \(a\) also lies above \(Z=1\) at higher pressure, but it starts from the ideal point and is not shown as clearly having only positive deviation throughout like \(b\) and \(c\).
Gases \(d, e,\) and \(f\) initially go below \(Z=1\), so they show negative deviation at some pressures.
Hence, they cannot be included.
Step 5: Final conclusion.
Thus, the gases showing only positive deviation from ideal behavior at all pressures are
\[ \boxed{b, c \text{ only}} \]
The graph shows variation of compressibility factor \(Z\) with pressure \(P\).
For an ideal gas,
\[ Z=1 \] at all pressures.
Step 2: Identify positive deviation.
A gas shows positive deviation from ideal behavior when
\[ Z\gt 1 \] This means the gas curve should remain above the line \(Z=1\) at all pressures.
Step 3: Observe the given curves.
From the graph, gases \(b\) and \(c\) remain above \(Z=1\) for all pressures.
Therefore, they show only positive deviation from ideal behavior.
Step 4: Eliminate other gases.
Gas \(a\) also lies above \(Z=1\) at higher pressure, but it starts from the ideal point and is not shown as clearly having only positive deviation throughout like \(b\) and \(c\).
Gases \(d, e,\) and \(f\) initially go below \(Z=1\), so they show negative deviation at some pressures.
Hence, they cannot be included.
Step 5: Final conclusion.
Thus, the gases showing only positive deviation from ideal behavior at all pressures are
\[ \boxed{b, c \text{ only}} \]
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