The question asks which named reaction converts an alkyl halide directly into an alkane. Let's look at what each of these four reactions actually does to its starting material.
Only the Wurtz reaction takes an alkyl halide as the starting material and delivers an alkane as the product, by coupling two alkyl fragments with sodium.
So the correct answer is Wurtz Reaction.
List I | List II | ||
|---|---|---|---|
| A | \(\Omega^{-1}\) | I | Specific conductance |
| B | \(∧\) | II | Electrical conductance |
| C | k | III | Specific resistance |
| D | \(\rho\) | IV | Equivalent conductance |
List I | List II | ||
|---|---|---|---|
| A | Constant heat (q = 0) | I | Isothermal |
| B | Reversible process at constant temperature (dT = 0) | II | Isometric |
| C | Constant volume (dV = 0) | III | Adiabatic |
| D | Constant pressure (dP = 0) | IV | Isobar |
List I | List II | ||
|---|---|---|---|
| A | \(\Omega^{-1}\) | I | Specific conductance |
| B | \(∧\) | II | Electrical conductance |
| C | k | III | Specific resistance |
| D | \(\rho\) | IV | Equivalent conductance |
List I | List II | ||
|---|---|---|---|
| A | Constant heat (q = 0) | I | Isothermal |
| B | Reversible process at constant temperature (dT = 0) | II | Isometric |
| C | Constant volume (dV = 0) | III | Adiabatic |
| D | Constant pressure (dP = 0) | IV | Isobar |