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after two hours one sixteenth of the starting amou
Question:
After two hours, one-sixteenth of the starting amount of a certain radioactive isotope is remained undecayed. The half-life of the isotope is
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Fraction remaining: ((1)/(2))ⁿ where n = number of half-lives.
BITSAT - 2017
BITSAT
Updated On:
Mar 20, 2026
15 minutes
30 minutes
45 minutes
4 hours
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The Correct Option is
B
Solution and Explanation
Step 1:
(1)/(16) = ((1)/(2))⁴
Step 2:
Four half-lives occur in 2 hours.
Step 3:
T₁/2 = (120)/(4) = 30 minutes
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