Question:
According to Bohr's atomic model, the angular momentum of an electron in the \(n^{\text{th}}\) orbit is
According to Bohr's atomic model, the angular momentum of an electron in the \(n^{\text{th}}\) orbit is
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Bohr's most important postulate:
\[
\boxed{mvr=\frac{nh}{2\pi}}
\]
For the first orbit:
\[
L=\frac{h}{2\pi}
\]
This is a frequently asked CUET question.
Updated On: Jun 8, 2026
- \(\dfrac{nh}{2\pi}\)
- \(\dfrac{h}{2\pi n}\)
- \(\dfrac{n^2h}{2\pi}\)
- \(\dfrac{h}{n}\)
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The Correct Option is A
Solution and Explanation
Step 1: Recall Bohr's quantization condition. According to Bohr, \[ mvr=\frac{nh}{2\pi} \] where \[ n=1,2,3,\ldots \]
Step 2: Identify the angular momentum. Angular momentum of the electron is: \[ L=mvr \] Hence, \[ L=\frac{nh}{2\pi} \]
Step 3: Choose the correct option. \[ \boxed{L=\frac{nh}{2\pi}} \] Therefore, \[ \boxed{\text{(A)}} \] is the correct answer.
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