Question

ABC is an isosceles triangle with AB=AC. Draw AP⊥BC to show that ∠B = ∠C.

Answer 1

In ∆APB and ∆APC, 

∠APB = ∠APC (Each 90º) 

AB =AC (Given) 

AP = AP (Common) 

∠∆APB ≅ ∠∆APC (Using RHS congruence rule) 

∠B = C (By using CPCT)