Question:
A Zener diode of breakdown voltage 20 V is connected as shown in the given circuit. The current through Zener diode is
A Zener diode of breakdown voltage 20 V is connected as shown in the given circuit. The current through Zener diode is
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Use current division rule and Ohm's law to find currents in Zener diode circuits.
Updated On: Jun 4, 2025
- 10 mA
- 4 mA
- 6 mA
- 8 mA
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The Correct Option is C
Solution and Explanation
Step 1: Circuit analysis
Supply voltage \(V = 40 V\), Zener voltage \(V_Z = 20 V\).
Voltage across \(2 k\Omega\) resistor: \[ V_R = V - V_Z = 40 - 20 = 20 V \] Step 2: Calculate current through resistor
\[ I = \frac{V_R}{R} = \frac{20}{2000} = 0.01 A = 10 mA \] Step 3: Current division
Current divides through \(5 k\Omega\) resistor and Zener diode.
Current through \(5 k\Omega\): \[ I_{5k} = \frac{V_Z}{5,000} = \frac{20}{5000} = 0.004 A = 4 mA \] Step 4: Current through Zener diode
\[ I_Z = I - I_{5k} = 10 mA - 4 mA = 6 mA \] Step 5: Conclusion
The current through Zener diode is 6 mA.
Supply voltage \(V = 40 V\), Zener voltage \(V_Z = 20 V\).
Voltage across \(2 k\Omega\) resistor: \[ V_R = V - V_Z = 40 - 20 = 20 V \] Step 2: Calculate current through resistor
\[ I = \frac{V_R}{R} = \frac{20}{2000} = 0.01 A = 10 mA \] Step 3: Current division
Current divides through \(5 k\Omega\) resistor and Zener diode.
Current through \(5 k\Omega\): \[ I_{5k} = \frac{V_Z}{5,000} = \frac{20}{5000} = 0.004 A = 4 mA \] Step 4: Current through Zener diode
\[ I_Z = I - I_{5k} = 10 mA - 4 mA = 6 mA \] Step 5: Conclusion
The current through Zener diode is 6 mA.
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