A uniform solid cylinder with radius \(R\) and length \(L\) has a moment of inertia \(I_1\) about the axis of the cylinder. A concentric solid cylinder of radius \(R' = \frac{R}{2}\) and length \(L' = \frac{L}{2}\) is carved out of the original cylinder. If \(I_2\) is the moment of inertia of the carved-out portion, then \(\frac{I_1}{I_2} =\)
(Both \(I_1\) and \(I_2\) are about the axis of the cylinder.)
The moment of inertia for a uniform solid cylinder about its axis is:
\[ I = \frac{1}{2} m R^2 \]
\[ I_1 = \frac{1}{2} m_1 R^2 \]
The mass of the carved-out portion (\(m_2\)) is proportional to its volume:
\[ m_2 = \rho \cdot \text{Volume} = \rho \cdot \pi \left(\frac{R}{2}\right)^2 \cdot \frac{L}{2} = \frac{\rho \pi R^2 L}{8} \]
Moment of inertia:
\[ I_2 = \frac{1}{2} m_2 \left(\frac{R}{2}\right)^2 = \frac{1}{2} \cdot \frac{\rho \pi R^2 L}{8} \cdot \frac{R^2}{4} = \frac{\rho \pi R^4 L}{64} \]
The mass of the original cylinder (\(m_1\)) is:
\[ m_1 = \rho \cdot \pi R^2 L \]
Moment of inertia of the original cylinder:
\[ I_1 = \frac{1}{2} m_1 R^2 = \frac{1}{2} \cdot \rho \pi R^2 L \cdot R^2 = \frac{\rho \pi R^4 L}{2} \]
The ratio is:
\[ \frac{I_1}{I_2} = \frac{\frac{\rho \pi R^4 L}{2}}{\frac{\rho \pi R^4 L}{64}} = \frac{64}{2} = 32 \]
The correct answer is 32.
I1=2m1R2I2=2m2(R/2)2
I2I1=m24m1=ρ⋅4πR2×2ℓ4⋅ρπR2ℓ⇒I2I1=32
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,



What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)
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The wheel or rotor of a motor, which appears in rotation motion problems, is a common example of the rotational motion of a rigid body.
Other examples: