Question:

A trickling filter receives an organic load of \(300~\mathrm{kg\ BOD/day}\) and has a filter volume of \(150~\mathrm{m^3}\). What is the organic loading rate of the filter?

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Organic loading rate: \[ \boxed{ \text{Organic Loading} = \frac{\text{BOD Load (kg/day)}}{\text{Filter Volume (m}^3\text{)}} } \]
Updated On: Jul 18, 2026
  • \(0.5~\mathrm{kg\ BOD/m^3\!\cdot\!day}\)
  • \(2~\mathrm{kg\ BOD/m^3\!\cdot\!day}\)
  • \(5~\mathrm{kg\ BOD/m^3\!\cdot\!day}\)
  • \(10~\mathrm{kg\ BOD/m^3\!\cdot\!day}\)
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The Correct Option is B

Solution and Explanation

Organic loading rate is \[ \text{Organic Loading} = \frac{\text{Organic Load}}{\text{Filter Volume}} \] Substituting the given values, \[ =\frac{300}{150} =2\ \mathrm{kg\ BOD/m^3\!\cdot\!day} \] Hence, \[ \boxed{2~\mathrm{kg\ BOD/m^3\!\cdot\!day}} \] Therefore, \[ \boxed{(B)} \]
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