Side of traffic signal board = a
Perimeter of the signal board = 3a = 180 cm
∴ a = 60 cm
Semi perimeter of the signal board (s) = \(\frac{3a}{2}\)
By using Heron’s formula,
Area of triangle =\(\sqrt{\text{[s(s - a)(s - b)(s - c)]}}\)
Area of given triangle
= \(\sqrt{\text{[s(s - a)(s - b)(s - c)]}}\)
=\( \sqrt{\text{[s(s - a)(s - a)(s - a)]}}\)
= \(\text{(s - a)} \sqrt{\text{[s(s - a)]}}\)
since s = \(\frac{3a}{2}\)
\((\frac{3a}{2} - a)\sqrt{\frac{3a}{2}(\frac{3a}{2} - a)}\)
\(= (\frac{a}{2}) \sqrt{\frac{3a}{2}(\frac{a}{2})}\)
\(= \frac{a}{2} × \frac{a}{2} × \sqrt3\)
=\( (\frac{\sqrt3}{4})a^2\)\( .......(1)\)
Area of the signal board = \( (\frac{\sqrt3}{4})a^2\) sq. units
perimeter = 180 cm
side of triangle = \(\frac{180}{3}\) cm
a = 60 cm
Area of the signal board = \( (\frac{\sqrt3}{4})(60)^2\)
\(= \)\( (\frac{\sqrt3}{4})(3600)\)
\(= 900\sqrt3\)
Area of the signal board \(= 900\sqrt3\) cm2
Length (in hours) | Number of lamps |
|---|---|
300 − 400 | 14 |
400 − 500 | 56 |
500 − 600 | 60 |
600 − 700 | 86 |
700 − 800 | 74 |
800 − 900 | 62 |
900 − 1000 | 48 |
(i) Represent the given information with the help of a histogram.
(ii) How many lamps have a lifetime of more than 700 hours?
Why was Santosh sent to the local school?