Question:
A trader marks an article \(25\%\) above its cost price and sells it by giving a discount of \(15\%\). If its selling price is ₹9350, then its cost price, in rupees, is:
A trader marks an article \(25\%\) above its cost price and sells it by giving a discount of \(15\%\). If its selling price is ₹9350, then its cost price, in rupees, is:
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For successive increase and decrease, multiply the percentage factors directly instead of calculating each amount separately.
Updated On: Jun 12, 2026
- \(7800\)
- \(7450\)
- \(8800\)
- \(8600\)
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Verified By Collegedunia
The Correct Option is C
Solution and Explanation
Concept:
Successive percentage changes are applied multiplicatively.
\[
\text{Selling Price}
=
\text{Cost Price}
\times
\left(1+\frac{\text{Markup}}{100}\right)
\times
\left(1-\frac{\text{Discount}}{100}\right)
\]
Step 1: Express the marked price in terms of cost price. Let the cost price be \(C\). Marked price: \[ =125\% \text{ of } C \] \[ =\frac{125}{100}C \] \[ =\frac54C \]
Step 2: Apply the discount. Discount \(=15\%\) Therefore selling price: \[ =\frac54C\times\frac{85}{100} \] \[ =\frac{425}{400}C \] \[ =\frac{17}{16}C \]
Step 3: Use the given selling price. \[ 9350=\frac{17}{16}C \] Hence, \[ C=9350\times\frac{16}{17} \] \[ =550\times16 \] \[ =8800 \] Therefore, \[ \boxed{₹8800} \]
Step 1: Express the marked price in terms of cost price. Let the cost price be \(C\). Marked price: \[ =125\% \text{ of } C \] \[ =\frac{125}{100}C \] \[ =\frac54C \]
Step 2: Apply the discount. Discount \(=15\%\) Therefore selling price: \[ =\frac54C\times\frac{85}{100} \] \[ =\frac{425}{400}C \] \[ =\frac{17}{16}C \]
Step 3: Use the given selling price. \[ 9350=\frac{17}{16}C \] Hence, \[ C=9350\times\frac{16}{17} \] \[ =550\times16 \] \[ =8800 \] Therefore, \[ \boxed{₹8800} \]
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