We can use the principle of inclusion and exclusion to solve this problem. Let:
- \( M \) be the set of students interested in Mathematics,
- \( P \) be the set of students interested in Physics,
- \( C \) be the set of students interested in Chemistry.
The total number of students interested in at least one of the three subjects is given by:
\[
|M \cup P \cup C| = |M| + |P| + |C| - |M \cap P| - |P \cap C| - |M \cap C| + |M \cap P \cap C|
\]
Substitute the given values:
\[
|M \cup P \cup C| = 150 + 200 + 175 - 50 - 60 - 40 + 30
\]
Simplifying:
\[
|M \cup P \cup C| = 405
\]
Thus, the number of students who are interested in at least one subject is 405. The total number of students is 450, so the number of students interested in Humanities is:
\[
450 - 405 = 45
\]
Thus, the number of students interested in Humanities is 45.