Question

What is the maximum percentage of people who can watch all the three channels?

• A. 12.5%
• B. 8.5%
• C. 15%
• D. Data insufficient
• A. 2%
• B. 5%
• C. 8.5%
• D. Cannot be determined
• A. 3.5%
• B. 0%
• C. 8.5%
• D. Cannot be determined

Answer 1

The Correct Option is C

We are told: $n(DD) = 80%$, $n(BBC) = 22%$, $n(CNN) = 15%$ of 200 people. The maximum possible number of people who can watch all three channels is limited by the smallest group’s size, which is CNN at 15%. Hence, the maximum possible percentage = $15%$.

Answer 2

We know: $n(DD \cap CNN) = 5%$, $n(DD \cap BBC) = 10%$. We are asked for $n(BBC \cap CNN \ \text{only}) = n(BBC \cap CNN) - n(BBC \cap CNN \cap DD)$. Since neither $n(BBC \cap CNN)$ nor the triple intersection is given, we cannot compute this value.

Answer 3

From the given data: $n(DD \cap CNN)$ and $n(DD \cap BBC)$ are known, but there is no information on $n(BBC \cap CNN)$ or $n(DD \cap BBC \cap CNN)$. Without knowing these, the triple intersection cannot be determined.