Let the total sum be represented by \( x \). The shares of P, Q, R, and S are in the ratio 5:2:4:3. The total number of parts is:
\[
5 + 2 + 4 + 3 = 14 \text{ parts}.
\]
So, the value of one part is:
\[
\frac{x}{14}.
\]
Now, it is given that R gets ₹1000 more than S. So, the difference between R's and S's share is:
\[
4\left(\frac{x}{14}\right) - 3\left(\frac{x}{14}\right) = \frac{x}{14}.
\]
This difference is ₹1000:
\[
\frac{x}{14} = 1000.
\]
Solving for \( x \):
\[
x = 1000 \times 14 = 14000.
\]
Now, the share of Q is:
\[
2\left(\frac{14000}{14}\right) = 2 \times 1000 = 2000.
\]
Thus, the share of Q is ₹2000.