P - sum and r- rate of interest
Simple Interest \(=\frac{prt}{100}\)
Compound interest:
Amount \(=P(1+\frac{r}{100})^n\)
\(p(\frac{r}{100})^2=40\)
\(P(\frac{r}{100})^2\times\frac{(300+r)}{100}=61\)
On Solving, we get
P= 8000 (sum). So the correct option is (C)
A man received Rs. 12000 as Puja Bonus. He invested a part of it at 5\(\%\) per annum and the remaining at 6\(\%\) per annum, simple interest being allowed in each case. The total interest earned by him in 4 years is Rs. 2580. The sum invested at 5\(\%\) per annum is