A straight wire of resistance $18~\Omega$ is bent in the form of an equilateral triangle. The effective resistance between any two vertices of the triangle is
Show Hint
Model the triangle as resistors in parallel and series between vertices.
Each side: $R = 18/3 = 6~\Omega$
Between any two points: one side direct ($6~\Omega$), two sides in series ($12~\Omega$) in parallel.
$R_{eq} = \dfrac{6 \cdot 12}{6 + 12} = \dfrac{72}{18} = 4~\Omega$