Step 1: Lacing force concept.
The transverse shear carried by lacing system is taken as \(2.5%\) of the axial load in the column.
Step 2: Calculation.
\[
\text{Shear} = 0.025 \times 125 = 3.125 \, \text{N (per lacing system side)}.
\]
Since lacing is provided on both faces:
\[
\text{Total transverse shear} = 2 \times 3.125 = 6.25 \, \text{N}.
\]
But by code provisions, design is generally based on **10% of axial load shared by lacing members in total**, hence:
\[
\text{Shear} = 0.10 \times 125 = 12.5 \, \text{N}.
\]
Step 3: Conclusion.
The lacing must resist a transverse shear of \(\,12.5 \, \text{N}\).
The solution(s) of the ordinary differential equation $y'' + y = 0$, is:
(A) $\cos x$
(B) $\sin x$
(C) $1 + \cos x$
(D) $1 + \sin x$
Choose the most appropriate answer from the options given below:
For the matrix, $A = \begin{bmatrix} -4 & 0 \\ -1.6 & 4 \end{bmatrix}$, the eigenvalues ($\lambda$) and eigenvectors ($X$) respectively are:
The value of $\iint_S \vec{F} \cdot \vec{N} \, ds$ where $\vec{F} = 2x^2y \hat{i} - y^2 \hat{j} + 4xz^2 \hat{k}$ and $S$ is the closed surface of the region in the first octant bounded by the cylinder $y^2 + z^2 = 9$ and the planes $x = 0, x = 2, y = 0, z = 0$, is:
The value of the integral $\displaystyle \oint_C \frac{z^3 - 6}{2z - i} \, dz$, where $C: |z| \leq 1$, is: