A stationary particle explodes into two particles of masses m1 and m2 which move in opposite directions with velocities v1 and v2. The ratio of their kinetic energies \(\frac{E_1}{E_2}\) is:
\(\frac{m_2}{m_1}\)
\(\frac{m_1}{m_2}\)
1
\(\frac{m_1v_2}{m_2v_1}\)
The Correct Option is A
Solution and Explanation
m1v1 = m2v2 (P1 = P2);
\(\frac{E_1}{E_2}=\frac{1}{2}\)
\(\frac{m_1v_1^2}{\frac{1}{2m_2v_2^2}}\)=\(\frac{\frac{P_1^2}{2m_1}}{\frac{P_2^2}{2m_2}}\)=\(\frac{m_2}{m_1}\)
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