Question:

A spring balance has a scale that reads 0 to 50 kg. The length of the scale is 20 cm. A body suspended from this spring, when displaced and released, oscillates with a period of 0.60 s. What is the weight of the body?

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Be careful not to confuse mass (kg) with weight (N).
Updated On: Apr 17, 2026
  • 22.36 N
  • 45 N
  • 219.13 N
  • 223.6 N
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The Correct Option is C

Solution and Explanation

Step 1: Concept
First find the spring constant ($k = F/x$), then use the time period formula $T = 2\pi\sqrt{m/k}$.
Step 2: Analysis
$k = \frac{50 \times 9.8}{0.20} = 2450$ N/m. Time period $T = 0.60$ s.
Step 3: Calculation
$0.60 = 2\pi\sqrt{m/2450} \Rightarrow m = \frac{(0.60)^{2} \times 2450}{4\pi^{2}} \approx 22.36$ kg. Weight $W = mg = 22.36 \times 9.8 \approx 219.13$ N.
Step 4: Conclusion
Hence, the weight is approximately 219.13 N.
Final Answer:(C)
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