A solution of two components containing n1 moles of the 1st component and n2 moles of the 2nd component is prepared. M1 and M2 are the molecular weights of component 1 and 2 respectively. If d is the density of the solution in g mL-1, C2 is the molarity and x2 is the mole fraction of the 2nd component, then C2 can be expressed as :
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- \(C_2 = \frac{1000\,x_2}{M_1 + x_2\left(M_2 - M_1\right)}\)
- \(C_2 = \frac{1000\,d\,x_2}{M_1 + x_2\left(M_2 - M_1\right)}\)
- \(C_2 = \frac{d\,x_2}{M_1 + x_2\left(M_2 - M_1\right)}\)
- \(C_2 = \frac{d\,x_1}{M_1 + x_2\left(M_2 - M_1\right)}\)
The Correct Option is B
Solution and Explanation
\(C_2 = \frac{n_2}{V_L} = \frac{1000\,d\,n_2}{n_1M_1 + n_2M_2}\).
Divide numerator and denominator by (n1 + n2), with x2 = n2/(n1+n2) and x1 = 1 - x2:
\(C_2 = \frac{1000\,d\,x_2}{x_1M_1 + x_2M_2} = \frac{1000\,d\,x_2}{M_1 + x_2(M_2 - M_1)}\).
Answer: (2) \(C_2 = \frac{1000\,d\,x_2}{M_1 + x_2(M_2 - M_1)}\)
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