A solid sphere of radius \(4a\) units is placed with its centre at origin. Two charges \(-2q\) at \((-5a, 0)\) and \(5q\) at \((3a, 0)\) is placed. If the flux through the sphere is \(\frac{xq}{\in_0}\) , find \(x\)
Step 1: Use Gauss's Law.
According to Gauss's law: \[ \Phi = \frac{q_{\text{enclosed}}}{\varepsilon_0} \] That means the electric flux through any closed surface depends only on the net charge enclosed by that surface.
The sphere is centered at the origin with radius \( 4a \), so its surface extends from: \[ x = -4a \text{ to } x = +4a \]
Now check the given charges:
Hence, the net enclosed charge inside the sphere: \[ q_{\text{enclosed}} = 5q \]
\[ \Phi = \frac{q_{\text{enclosed}}}{\varepsilon_0} = \frac{5q}{\varepsilon_0} \] So, comparing with given expression: \[ \Phi = \frac{xq}{\varepsilon_0} \] We get: \[ x = 5 \]
\[ \boxed{x = 5} \]
The Correct answer is : 5
From Gauss law
\(\phi=\frac{q_{enclosed}}{ε_0}=\frac{5q}{ε_0}\)
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,


What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)
It is the property of subatomic particles that experiences a force when put in an electric and magnetic field. It is are of two types: Positive and Negative. It commonly carried by charge carriers protons and electrons.
Various properties of charge include the following :-
Two kinds of electric charges are there :-
When there is an identical number of positive and negative charges, the negative and positive charges would cancel out each other and the object would become neutral.