Question:

A solid cylinder rolls down an incline without slipping. Its acceleration depends on

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For rolling without slipping, \[ a=\frac{g\sin\theta}{1+\dfrac{I}{mR^2}}. \] For a solid cylinder, \[ I=\frac12 mR^2 \] which gives \[ a=\frac23 g\sin\theta. \] Notice that the mass cancels out.
Updated On: Jul 29, 2026
  • Only the mass of the cylinder
  • Only gravitational acceleration
  • Both the mass of the cylinder and the angle of inclination
  • Both the angle of inclination and gravitational acceleration
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The Correct Option is D

Solution and Explanation

Concept: For a rigid body rolling down an incline without slipping, \[ a=\frac{g\sin\theta}{1+\dfrac{I}{mR^2}}. \] Thus the acceleration depends on \(g\), the angle of inclination \(\theta\), and the shape of the body.

Step 1: Write the moment of inertia of a solid cylinder. \[ I=\frac12 mR^2. \] Substituting into the rolling acceleration formula, \[ a = \frac{g\sin\theta} {1+\dfrac12}. \] \[ a = \frac{2}{3}g\sin\theta. \]

Step 2: Identify the quantities on which acceleration depends. From \[ a=\frac{2}{3}g\sin\theta, \] the acceleration depends on \[ g \] and \[ \theta. \] It does not depend on \[ m \] or \[ R. \]

Step 3: Choose the correct option. Since \[ a=\frac{2}{3}g\sin\theta, \] the acceleration depends on both gravitational acceleration and the angle of inclination. Therefore, \[ \boxed{\text{Acceleration depends on }g\text{ and }\theta} \] \[ \boxed{\text{Answer = (D)}} \]
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