Concept:
For a rigid body rolling down an incline without slipping,
\[
a=\frac{g\sin\theta}{1+\dfrac{I}{mR^2}}.
\]
Thus the acceleration depends on \(g\), the angle of inclination \(\theta\), and the shape of the body.
Step 1: Write the moment of inertia of a solid cylinder.
\[
I=\frac12 mR^2.
\]
Substituting into the rolling acceleration formula,
\[
a
=
\frac{g\sin\theta}
{1+\dfrac12}.
\]
\[
a
=
\frac{2}{3}g\sin\theta.
\]
Step 2: Identify the quantities on which acceleration depends.
From
\[
a=\frac{2}{3}g\sin\theta,
\]
the acceleration depends on
\[
g
\]
and
\[
\theta.
\]
It does not depend on
\[
m
\]
or
\[
R.
\]
Step 3: Choose the correct option.
Since
\[
a=\frac{2}{3}g\sin\theta,
\]
the acceleration depends on both gravitational acceleration and the angle of inclination.
Therefore,
\[
\boxed{\text{Acceleration depends on }g\text{ and }\theta}
\]
\[
\boxed{\text{Answer = (D)}}
\]